Alphabet Z shape pattern in java
Steps to do this:-
1. take 3 integers i,j,n (i and j is for loop and n is for user input length)2. take the length from user
3.start the i loop (i=1;i<=n;i++) and start the j loop inside i loop
(j=1;j<=n;j++) now check this inside j loop that
if(i==1|| i==n|| i+j==n+1)
{
print "*";
}
else
{
print " ";
}
close the j loop and print a new line inside i loop..
i is for printing rows and j is for printing coloumn
Explanation:-
when we check if (i==1) it will print the first row
***********
when we check if (i==1) it will print the last row
***********
when we check if (i+j==n+1) it will print the right to left line
*
*
*
*
*
and it will print z
4. save ad run
The Source Code
import java.util.Scanner;
class zpatt
{
public static void main(String[] args) {
Scanner s=new Scanner(System.in);
int i,j,n;
System.out.println("enter the length");
n=s.nextInt();
for(i=1;i<=n;i++)
{
for(j=1;j<=n;j++)
{
if(i==1||i==n||i+j==n+1)
{
System.out.print("*");
}
else
{
System.out.print(" ");
}
}
System.out.println();
}
}
}
OUTPUT
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