Super Number in java

Checking Super Number 

Steps to do this:-

1. take 4 integers x,n,sum,r ;// (n is for user input number x will store the n's value sum will calculate the addition of the each numbers and r will store the remainder  )

2. take a value from user

3.and do this
while(n>=10)
{
x=n;
sum=0;
while(x>0)
{
r=x%10;
sum=sum+r;
x=x/10;
}
n=sum;
}

first we start while(n>=10) here we store the n's value in x and we do sum=0 because, we start the loop from n>=10 it means if n is <=9 the loop will terminate and we can get a single digit value 

and we just put the user input value in x and initialize sum=0 then we just start the simple while loop to calulate each digit sum and the sum we stored in n

now if n is <=9 then the loop will be terminated and if not then loop will be restart until we get a single digit value inside n

4. now print " the super digit is"+n outside the all loop 
5.save and run

The Source Code

import java.util.Scanner;
class superd
{
    public static void main(String[] args) {
        Scanner s=new Scanner(System.in);
        int x;
        int n,sum,r;
        // x is for to store n's value which will be user input
        //sum is for calculating the each digit sum
        // r is for remainder
        System.out.println("enter the Number");
        n=s.nextInt();
        while(n>=10)
        {
            x=n;
            sum=0;
           
            while(x>0)
            {
                r=x%10;
                sum=sum+r;
                x=x/10;
            }
            n=sum;
        }
        System.out.println("the super digit of the given number is "+n);
    }
}

OUTPUT

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