I pattern in java

Printing I pattern 

Steps to do this:-

1. take 3 integers i,j,n ( i and j is for loop and n is for user input length )

2.now take the input from user

3.start the i loop (i=1;i<=n;i++) and start the j loop inside the i loop (j=1;j<=n;j++) 

 i is for printing row and j is for printing coloumn 

3. now check in j loop that if(i== 1|| i==n || j==(n/2)) and print "*"
else print " " (a blank string ) close the j loop and print a new line inside i loop

when,i==1 will check it will print the 1st row
when,i==n will check it will print the last row
when,j==n/2 will check it will print the middle column

4.save and run 

The Source Code

import java.util.Scanner;
class i
{
    public static void main(String[] args) {
        Scanner s=new Scanner(System.in);
        int i,j,n;// i and j is for loop and n is for user input
        System.out.println("enter the number");
        n=s.nextInt();
        for(i=1;i<=n;i++)
        {
            for (j=1;j<=n ;j++ ) {
                if(i==1||i==n||j==(n/2))
                {
                    System.out.print("*");
                }
                else
                {
                    System.out.print(" ");
                }
               
            }
            System.out.println();
        }
    }
}

OUTPUT

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