Pronic Number Checking in java

Checking Pronic  number 

 Steps to do this:-

1. take two integers i and n (n is for user input number i is for loop and calculating the consecutive number multiplication )

2. take a boolean value b=false;

3.take the user input value

4.start the for loop (i=1;i<=n;i++) now check this 
if(i*(i+1)==n)
{
b=true;
break;
}

close the for loop and check
if(b) // here b is true
{
print"this is prionic number"
}
else 
{
print "this is not a prionic number"
}
now the loop will run from 1 to user input number 
suppose user input 30
then the loop will run i=1to4 and it will not match the answer, but when the i=5 then 
if(5*(5+1)==30 // 30==30
then b will be true loop will break, and it will print that 30 is prionic number because 30 is the product of 5 and 6 two consecutive numbers

5.save and run

The Source Code

import java.util.Scanner;
class prionic
{
    public static void main(String[] args) {
        Scanner s=new Scanner(System.in);
        int i,n;// i is for loop and n is for the number which will be user input
        boolean b=false;// for condition checking
        System.out.println("enter the number");
        n=s.nextInt();
        for(i=0;i<=n;i++)
        {   
            if(i*(i+1)==n)
            {
                b=true;
                break;
            }

        }
        if(b)
        {
            System.out.println("the number you entered "+n+" is the product of "+i+" and "+(i+1));
            System.out.println("those are consecutive number ");
            System.out.println("this is a prionic number");
        }
        else{
            System.out.println("the number is not a product of two consecutive number");
            System.out.println("this is not a prionic number");
        }
    }
}

OUTPUT

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