How to check Armstrong number in java

Checking Armstrong number

 

Steps to do this:-  

1.take n,i,sum=0,r. we have to initialize sum with 0. n is for user input .i is for storing n's value . r is for storing remainder.

2.store the user value in i

 3.start while loop (n>0) and do this

r=n%10 it will take last value from the number (if 153 is entered then first time r will store 3)

n=n/10, it will eliminate the last number ( n is now 15)

sum=sum+(r*r*r) (sum=0+3*3*3*)

4.Check if  (sum==i) then print "this an Armstrong  number" 

else

print "this is not an Armstrong  number"

5. save and run

The Source Code

import java.util.Scanner;
class arm
{
  public static void main(String[] args) 

{
   Scanner s=new Scanner(System.in);
        int n,i,r,sum=0;// n is for input i is for storing n's value r is for remainder sum is for ans
        System.out.println("enter the number");
        n=s.nextInt();
        i=n;
        while(n>0)
        {
            r=n%10;
            n=n/10;
            sum=sum+(r*r*r);
        }
        if(sum==i)
        {
            System.out.println("this is an armstrong number");
        }
        else
        {
            System.out.println("this is not an armstrong number");
        }
    }
}

OUTPUT

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